document.write( "Question 1195502: In a different plan for area codes the first digit could be any number from 2 through 6 and the second digit was either a 3 or a 4 and the third digit could be any number expect 3,4 or 8 with this plan how many differnt area codes are possible \n" ); document.write( "

Algebra.Com's Answer #828004 by ikleyn(52790) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "

\r\n" );
document.write( "\r\n" );
document.write( "    (6-2+1)*(4-3+1)*(10-3) = 5*2*7 = 70 different area codes are possible.   ANSWER\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );