document.write( "Question 1195465: Gabriella’s age is half that of her brother Sam. Four years ago, Gabriella’s age was a third that of her brother. How old was Sam two years ago
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Algebra.Com's Answer #827960 by ikleyn(52790)\"\" \"About 
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\n" ); document.write( "Gabriella’s age is half that of her brother Sam.
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document.write( "Let x be the Sam's age now.\r\n" );
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document.write( "Then Gabriela's age is x/2 years, according to the problem.\r\n" );
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document.write( "Four years ago Sam was x-4 years old;  Gabriela was \"x%2F2-4\" years old.\r\n" );
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document.write( "The problem says that\r\n" );
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document.write( "    \"x%2F2-4\" = \"%281%2F3%29%2A%28x-4%29\".\r\n" );
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document.write( "It is your base equation.\r\n" );
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document.write( "To rid of the denominators, multiply both sides by 4*3 = 12.  You will get then\r\n" );
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document.write( "    6x - 48 = 4x - 16\r\n" );
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document.write( "    6x - 4x = 48 - 16\r\n" );
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document.write( "       2x   =    32\r\n" );
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document.write( "        x   =    32/2 = 16.\r\n" );
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document.write( "So, now Sam is 16 years old; Gabriela is 16/2 = 8 years old.\r\n" );
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document.write( "You may check that the condition \"4 years ago\" is held.\r\n" );
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document.write( "ANSWER.  Two years ago, Sam was 16-2 = 14 years old.\r\n" );
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