document.write( "Question 17047: 1/3(9b+1)=b-1
\n" ); document.write( "3b+1/3=b-1
\n" ); document.write( "-b -b
\n" ); document.write( "2b+1/3=-1
\n" ); document.write( " +1 +1
\n" ); document.write( "2b+4/3=2/3b
\n" ); document.write( "

Algebra.Com's Answer #8279 by tjnw79(57)\"\" \"About 
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1/3(9b+1)=b-1
\n" ); document.write( "first times (1/3)9b and (1/3)1 to get
\n" ); document.write( "3b+1/3=b-1
\n" ); document.write( "then you want to subtract the b from both sides
\n" ); document.write( "2b+1/3=-1
\n" ); document.write( "now you want to -1/3 to both sides
\n" ); document.write( "2b=2/3
\n" ); document.write( "divide the 2 on both sides
\n" ); document.write( "b=2/6 or simplified 1/3
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