document.write( "Question 1195397: Solve for x in the equation 5^(2x+3)-6(5^x )=595 \n" ); document.write( "
Algebra.Com's Answer #827877 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "\"5%5E%282x%2B3%29-6%285%5Ex+%29=595\"

\n" ); document.write( "The equation involves 5 to the powers (2x+3) and x. Rewrite the equation as a \"quadratic\" with \"variable\" 5^x by writing \"5%5E%282x%2B3%29\" as \"%285%5E3%29%285%5E%282x%29%29\".

\n" ); document.write( "\"125%285%5E%282x%29%29-6%285%5Ex%29-595=0\"

\n" ); document.write( "The quadratic does not factor over the integers; a graphing calculator shows

\n" ); document.write( "\"5%5Ex=2.2058744\" to several decimal places. Then

\n" ); document.write( "\"x%2Alog%285%29=log%282.2058744%29\"
\n" ); document.write( "\"x=log%282.2058744%29%2Flog%285%29=0.4915529686\" again to several decimal places.

\n" ); document.write( "ANSWER: x = approximately 0.4915529686

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