document.write( "Question 1195365: Hello, again. I hope I’m remembering this question as it appeared on my test. \r
\n" ); document.write( "\n" ); document.write( "Two men leave from point A. The first man heads east at a rate of 20mph. The second man, leaving 30 minutes after the first man, heads south at a rate of 10Mph. What is their total distance apart after 2hours?\r
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Algebra.Com's Answer #827836 by ikleyn(52790) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "Hello, again. I hope I’m remembering this question as it appeared on my test.
\n" ); document.write( "Two men leave from point A. The first man heads east at a rate of 20mph.
\n" ); document.write( "The second man, leaving 30 minutes after the first man, heads south at a rate of 10Mph.
\n" ); document.write( "What is their total distance apart after 2hours?
\n" ); document.write( "Thanks again!
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document.write( "First man traveled 20 mph * 2 hours = 40 miles East.\r\n" );
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document.write( "Second man traveled 10 mph * 1.5 hours = 15 miles South.\r\n" );
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document.write( "To find the distance, use the Pythagoras\r\n" );
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document.write( "    distance =  = 42.72 miles.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved and thoroughly explained.\r
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