document.write( "Question 1195317: Zheng went to the park traveling 6 mph and returned home traveling 4 mph. If the total trip took 5 hours, how long did Zheng travel at each speed? \n" ); document.write( "
Algebra.Com's Answer #827792 by greenestamps(13202)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "If a formal algebraic solution is required, then you can set the problem up something like what is shown in the response from tutor @josgarithmetic.

\n" ); document.write( "But if formal algebra is not needed, a quick mental solution like the one shown in the response from tutor @ikleyn can be used.

\n" ); document.write( "(A further note about that.... Solving the problem mentally gives you more good brain exercise than using formal algebra.)

\n" ); document.write( "Following is a solution method essentially the same as the one from tutor @ikleyn, presented a bit differently, which might (or might not) be easier to understand.

\n" ); document.write( "The distances are the same, so if the ratio of speeds is A:B then the ratio of times is B:A.

\n" ); document.write( "The ratio of the two speeds is 6:4 = 3:2, so the ratio of times is 2:3.
\n" ); document.write( "A total of 5 hours divided into two parts in the ratio 2:3 is obviously 2 hours and 3 hours. So he traveled for 2 hours at the higher speed an 3 hours at the lower speed.

\n" ); document.write( "ANSWER: 2 hours at 6mph; 3 hours at 4mph

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