document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1195305>Question 1195305</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Brown can plant his lettuces in an hour and a half.His <BR>\n" );
document.write( "son could plant them in two and a half hours.How<BR>\n" );
document.write( "long would it take them if they worked together? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #827769 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=827769\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is a very different way to solve \"working together\" problems like this.<br><BR>\n" );
document.write( "Consider a convenient common multiple of the two given times for the two workers working alone.  For this problem, 15 hours is a nice choice: 1.5*10 = 15; 2.5*6 = 15.<br><BR>\n" );
document.write( "In 15 hours, Brown could do the whole job 15/1.5 = 10 times; in 15 hours his son could do the whole job 15/2.5 = 6 times.<BR>\n" );
document.write( "So together in 15 hours the two could do the whole job 10+6 = 16 times.<BR>\n" );
document.write( "So to do the single whole job once would take them 15/16 hours.<br><BR>\n" );
document.write( "ANSWER: 15/16 hours<br><BR>\n" );
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