document.write( "Question 113764This question is from textbook Algebra Structure and method
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document.write( ": At 8:00 a.m the Smith's left a campground,driving at 48mi/h. At 8:20 a.m the Garcia's left the same campground and followed the same route, driving at 60 mi/h. At what time did they overtake the Smith's?
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document.write( "Here is what I have but I don't know if it is right
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document.write( "60t=48(t+1/3)
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document.write( "60t=48t+16
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document.write( "60t-48t=48t-48t+16
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document.write( "12t=16
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document.write( "12t/12=16/12
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document.write( "t=14/12or 11/3
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document.write( "They overtook the Smiths at 1:20
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document.write( "Is this right? \n" );
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Algebra.Com's Answer #82773 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! The Smiths and Garcias both travel the same distance \n" ); document.write( " \n" ); document.write( "To find their elapsed time, start a stopwatch when the \n" ); document.write( "Garcias leave at 8:20. Stop the stopwatch when they meet. \n" ); document.write( "Call that elapsed time \n" ); document.write( "driving for 20 min., so their time is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This is the Garcias elapsed time \n" ); document.write( "8:20 + 1 hr 20 min = 9:40 answer \n" ); document.write( " \n" ); document.write( " |