document.write( "Question 1195267: The velocity v, in meters per second, of a falling object on Earth after t seconds, ignoring the effect of air resistance, is modeled by the equation v = 9.8t. There is a different linear relationship between time and velocity on Mars, as shown in the table below.  \r
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\n" ); document.write( "\n" ); document.write( "Time || Velocity on Mars
\n" ); document.write( "(second) || (meters per second)
\n" ); document.write( "0 || 0
\n" ); document.write( "4 || 14.8
\n" ); document.write( "8 || 29.6\r
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\n" ); document.write( "\n" ); document.write( "If an object dropped toward the surface of Earth has a velocity of 58.8 meters per second after t seconds, what would be the velocity of the same object dropped toward the surface of Mars after t seconds, ignoring the effect of air resistance?  
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Algebra.Com's Answer #827690 by Alan3354(69443)\"\" \"About 
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The velocity v, in meters per second, of a falling object on Earth after t seconds, ignoring the effect of air resistance, is modeled by the equation v = 9.8t. There is a different linear relationship between time and velocity on Mars, as shown in the table below. \r
\n" ); document.write( "\n" ); document.write( "Time || Velocity on Mars
\n" ); document.write( "(second) || (meters per second)
\n" ); document.write( "0 || 0
\n" ); document.write( "4 || 14.8
\n" ); document.write( "8 || 29.6\r
\n" ); document.write( "\n" ); document.write( "If an object dropped toward the surface of Earth has a velocity of 58.8 meters per second after t seconds, what would be the velocity of the same object dropped toward the surface of Mars after t seconds, ignoring the effect of air resistance?
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\n" ); document.write( "v = 9.8t = 58.8
\n" ); document.write( "t = 6 seconds
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\n" ); document.write( "On Mars:
\n" ); document.write( "14.8/4 = 3.7 m/sec/sec
\n" ); document.write( "6*3.7 = 22.2 m/sec
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