document.write( "Question 1195267: The velocity v, in meters per second, of a falling object on Earth after t seconds, ignoring the effect of air resistance, is modeled by the equation v = 9.8t. There is a different linear relationship between time and velocity on Mars, as shown in the table below. \r
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document.write( "Time || Velocity on Mars
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document.write( "(second) || (meters per second)
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document.write( "0 || 0
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document.write( "4 || 14.8
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document.write( "8 || 29.6\r
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document.write( "If an object dropped toward the surface of Earth has a velocity of 58.8 meters per second after t seconds, what would be the velocity of the same object dropped toward the surface of Mars after t seconds, ignoring the effect of air resistance? \n" );
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Algebra.Com's Answer #827690 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! The velocity v, in meters per second, of a falling object on Earth after t seconds, ignoring the effect of air resistance, is modeled by the equation v = 9.8t. There is a different linear relationship between time and velocity on Mars, as shown in the table below. \r \n" ); document.write( "\n" ); document.write( "Time || Velocity on Mars \n" ); document.write( "(second) || (meters per second) \n" ); document.write( "0 || 0 \n" ); document.write( "4 || 14.8 \n" ); document.write( "8 || 29.6\r \n" ); document.write( "\n" ); document.write( "If an object dropped toward the surface of Earth has a velocity of 58.8 meters per second after t seconds, what would be the velocity of the same object dropped toward the surface of Mars after t seconds, ignoring the effect of air resistance? \n" ); document.write( "---------------- \n" ); document.write( "v = 9.8t = 58.8 \n" ); document.write( "t = 6 seconds \n" ); document.write( "--- \n" ); document.write( "On Mars: \n" ); document.write( "14.8/4 = 3.7 m/sec/sec \n" ); document.write( "6*3.7 = 22.2 m/sec \n" ); document.write( " |