document.write( "Question 1195258: Evaluate the following Inverse Trigonometric Function.
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Algebra.Com's Answer #827684 by ikleyn(52788)\"\" \"About 
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document.write( "(a) \"sin%5E%28-1%29+%28-1%29\" = \"-+pi%2F2\"     ( since  \"sin%28-+pi%2F2%29\" = \"-1\" ).\r\n" );
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document.write( "(b) \"tan%5E%28-1%29+%28-1%29\" = \"-+pi%2F4\"     ( since  \"tan%28-+pi%2F4%29\" = \"-1\" ).\r\n" );
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\n" ); document.write( "\n" ); document.write( "In this post,  I treat  \"sin%5E%28-1%29+%28x%29\"  as  arcsin(x)  and treat  \"tan%5E%28-1%29+%28x%29\"  as  arctan(x).\r
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