document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1195247>Question 1195247</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The bearing of point A from B is 138° and the bearing of A from C is 228°. Given that the length AB=8.4cm and AC=9.8cm , calculate the bearing of B from C </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #827671 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=827671\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The bearing of point A from B is 138° and the bearing of A from C is 228°. Given that the length AB=8.4cm and AC=9.8cm, calculate the bearing of B from C<BR>\n" );
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document.write( "Angle at A = 228 - 138 = 90 degs, a right triangle<BR>\n" );
document.write( "tan(C) = 8.4-9.8 = 6/7<BR>\n" );
document.write( "Angle C = ~ 40.6 degs<BR>\n" );
document.write( "Bearing from B to C = (228 - 180) + 40.6 = 88.6 degs<BR>\n" );
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