document.write( "Question 1195227: Suppose a function \"f\" is such that \"f%281%2Fx%29-3f%28x%29=x\" for every x≠0(x that does not equal 0). Find \"f%282%29\". \n" ); document.write( "
Algebra.Com's Answer #827648 by ikleyn(52798)\"\" \"About 
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\n" ); document.write( "Suppose a function f is such that f(1/x)-3f(x)=x for every x≠0 (x that does not equal 0). Find f(2).
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document.write( "Write the given functional equation for x = 2 and for x = 1/2.\r\n" );
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document.write( "For x = 2, you will have\r\n" );
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document.write( "    f(1/2) - 3f(2) = 2              (1)\r\n" );
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document.write( "For x = 1/2, you will have\r\n" );
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document.write( "    f(1/(1/2)) - 3f(1/2) = 1/2,  \r\n" );
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document.write( "or\r\n" );
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document.write( "    f(2) - 3f(1/2) = 1/2.           (2)\r\n" );
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document.write( "Let  u = f(1/2),  v = f(2)  for breavity.  Then you can re-write (1) and (2) in the form\r\n" );
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document.write( "    u - 3v = 2                       (3)\r\n" );
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document.write( "    v - 3u = 1/2                     (4)\r\n" );
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document.write( "Now I want to solve the system of linear equations (3) and (4) and find v.\r\n" );
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document.write( "For it, I express  u = 2+ 3v  from (3) and substitute it into equation (4)\r\n" );
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document.write( "    v - 3*(2+3v) = 1/2.\r\n" );
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document.write( "In the last equation, multiply both sides by 2 to run from denominator\r\n" );
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document.write( "    2v - 6*(2+3v) = 1\r\n" );
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document.write( "Simplify and find v\r\n" );
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document.write( "    2v - 12 - 18v = 1\r\n" );
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document.write( "        -16v      = 1 + 12\r\n" );
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document.write( "        -16v      =   13\r\n" );
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document.write( "           v      =   \"-13%2F16\".\r\n" );
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document.write( "Thus  v = f(2) = \"-13%2F16\",  and the problem is just solved.\r\n" );
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document.write( "ANSWER.  f(2) = \"-13%2F16\".\r\n" );
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