document.write( "Question 1195194: A woman invested 4 times as much at 3% as she did at 2%. The total amount of interest she earns in 1 year from both accounts is $1,120. How much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #827604 by ikleyn(52787)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "A woman invested 4 times as much at 3% as she did at 2%. \n" ); document.write( "The total amount of interest she earns in 1 year from both accounts is $1,120. \n" ); document.write( "How much did she invest at each rate? \n" ); document.write( "~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "She invested x dollars at 2% and 4x dollars at 3%.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Write the total annual interest equation\r\n" ); document.write( "\r\n" ); document.write( " 0.02x + 0.03*(4x) = 1120 dollars.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Simplify and find x\r\n" ); document.write( "\r\n" ); document.write( " 0.02x + 0.12x = 1120\r\n" ); document.write( "\r\n" ); document.write( " 0.14x = 1120\r\n" ); document.write( "\r\n" ); document.write( " x = 1120/0.14 = 8000.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "ANSWER. $8000 invested at 2% and $32000 invested at 3%\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |