document.write( "Question 1195186: The diameter of a brand of tennis balls is approximately normally distributed, with a mean of 2.63 inches and a standard deviation of 0.03 inch. If you select a random sample of nine tennis balls,
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document.write( "a. what is the sampling distribution of the mean?
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document.write( "b. what is the probability that the sample mean is less than 2.61 inches?
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document.write( "c. what is the probability that the sample mean is between 2.62 and 2.64 inches?
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document.write( "d. The probability is 60% that the sample mean will be between what two values symmetrically distributed around the population mean?
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Algebra.Com's Answer #827601 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! The mean of the sampling distribution of n=9 is still 2.63 inches. The sd is 0.03/sqrt(9) or 0.01 inch. \n" ); document.write( "The probability of the sample mean < 2.61 inches is (2.61-2.63)/0.01=z and z <=-2. This has probability of 0.0228. \n" ); document.write( "- \n" ); document.write( "Between 2.62 and 2.64 inches is z between -1 and +1 with probability of 0.6836 \n" ); document.write( "- \n" ); document.write( "z(0.2)=-0.8416 and z(0.8)=0.8416 \n" ); document.write( "so z=(x-mean)/sd \n" ); document.write( "0.8416=(x-2.63)/0.01 \n" ); document.write( "0.08416=x-2.63 \n" ); document.write( "x=2.638 inches for the upper limit \n" ); document.write( "x=2.546 inches for the lower limit \n" ); document.write( "Those two values enclose the sample mean symmetrically. \n" ); document.write( " |