document.write( "Question 1194388: A woman borrows $1500, agreeing to pay $100 at the end of each month to reduce the outstanding principal and agreeing to pay the interest due on any unpaid balance at a rate of 12% per annum (i.e. 1% per month). Determine the sum of all interest payments. \n" ); document.write( "
Algebra.Com's Answer #827596 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
the loan is 1500.
\n" ); document.write( "the payments are 100 at the end of each month.
\n" ); document.write( "the interest rate is 12% per year / 12 = 1% per month.
\n" ); document.write( "the number of months required to pay off the loan is equal to 16.33301765.
\n" ); document.write( "total payments are that * 100 = 1633.01765.
\n" ); document.write( "total interest is 1633.01765 minus 1500 = 133.01765.
\n" ); document.write( "i used the ti-ba-ii financial calculator.
\n" ); document.write( "inputs were:
\n" ); document.write( "present value = 1500
\n" ); document.write( "future value = 0
\n" ); document.write( "payment at the end of each month = -100
\n" ); document.write( "interest rate per month = 1%
\n" ); document.write( "output was number of months.
\n" ); document.write( "let me know if you have any questions.
\n" ); document.write( "theo\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );