document.write( "Question 1195149: Rock puts $1000 in the bank for two years at 10% interest compounded annually. At the end of the two years, what will be her balance? \n" ); document.write( "
Algebra.Com's Answer #827534 by ikleyn(52790)\"\" \"About 
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\n" ); document.write( "Rock puts $1000 in the bank for two years at 10% interest compounded annually.
\n" ); document.write( "At the end of the two years, what will be her balance?
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\n" ); document.write( "\n" ); document.write( "            @MathLover1 read, interpreted and solved the problem incorrectly,\r
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document.write( "As written, the text means that the interest is 10% annually, compounded annually.\r\n" );
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document.write( "So, after one year, the amount at the account is  1.1*1000 = 1100 dollars, after fisrt compounding.\r\n" );
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document.write( "After two years, the amount at the account is  \"1.1%5E2%2A1000\" = 1.21*1000 = 1210 dollars, after second compounding.\r\n" );
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document.write( "ANSWER. After two years, the balance will be 1210 dollars.\r\n" );
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\n" ); document.write( "\n" ); document.write( "To see many other similar  (and different)  solved problems on compounded interest accounts,  look into the lesson\r
\n" ); document.write( "\n" ); document.write( "    - Compounded interest percentage problems \r
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