document.write( "Question 1195149: Rock puts $1000 in the bank for two years at 10% interest compounded annually. At the end of the two years, what will be her balance? \n" ); document.write( "
Algebra.Com's Answer #827532 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"A+=+P%281+%2B+r%2Fn%29%5E%28nt%29\"\r
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\n" ); document.write( "\n" ); document.write( "given:
\n" ); document.write( "\"P=1000\"
\n" ); document.write( "\"t=2\" years
\n" ); document.write( "\"R=5\"%
\n" ); document.write( "\"n=1\" \r
\n" ); document.write( "\n" ); document.write( "First, convert rate \"R\" as a percent to \"r\" as a decimal
\n" ); document.write( "\"r+=+R%2F100\"
\n" ); document.write( "\"r+=+5%2F100\"
\n" ); document.write( "\"r+=+0.05\" rate per year,\r
\n" ); document.write( "\n" ); document.write( "Then solve the equation for \"A\"\r
\n" ); document.write( "\n" ); document.write( "\"A+=+P%281+%2B+r%2Fn%29%5E%28nt%29%0D%0A%7B%7B%7BA+=+1000.00%281+%2B+0.05%2F1%29%281%2A2%29\"
\n" ); document.write( "\"A+=+1000.00%281+%2B+0.05%29%282%29\"
\n" ); document.write( "\"A+=+1102.50\"\r
\n" ); document.write( "\n" ); document.write( "after two years, her balance will be \"+1102.50\"\r
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