document.write( "Question 1195129: six student write an exam.the average score obtained on the exam by the group of students is 71% if the first two students each obtained a mark of 73% while the next three students each obtain a mark of 68% what was the mark obtained by the sixth student?
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Algebra.Com's Answer #827497 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "(1) A standard solution method, using the standard method of calculating averages....

\n" ); document.write( "2 scores of 73, plus 3 scores of 68, plus 1 score of x, makes an average of 71:

\n" ); document.write( "\"%28%282%2A73%29%2B3%2868%29%2B1%28x%29%29%2F6=71\"
\n" ); document.write( "\"%28146%2B204%2Bx%29%2F6=71\"
\n" ); document.write( "\"350%2Bx=426\"
\n" ); document.write( "\"x=426-350=76\"

\n" ); document.write( "ANSWER: 76

\n" ); document.write( "(2) An alternative method that keeps the numbers in the calculations smaller, which can be used in any problem like this where the numbers are all close together....

\n" ); document.write( "Compare each number to the average and look at the \"overs\" and \"unders\". The average is obtained only if the overs and unders are equal.

\n" ); document.write( "2 scores of 73, each 2 over the average: +4
\n" ); document.write( "3 scores of 68, each 3 under the average: -9

\n" ); document.write( "The balance with those 5 scores is (+4)+(-9) = -5; that means the 6th score must be +5.

\n" ); document.write( "ANSWER: 71+5 = 76

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