document.write( "Question 1195113: A manufacturer packages vegetables in cans that are in the shape of right cylinders with height 15 centimeters and volume 750 cubic centimeters. If the manufacturer reduces the volume of the cans to 600 cubic centimeters but keeps the area of the base the same, by how many centimeters does the height of the can decrease?
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Algebra.Com's Answer #827486 by ikleyn(52780)\"\" \"About 
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\n" ); document.write( "A manufacturer packages vegetables in cans that are in the shape of right cylinders
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document.write( "The original volume equation for the cylindrical can is\r\n" );
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document.write( "    750 = B*H,     (1)\r\n" );
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document.write( "where B is the base area and H is the height of the cylinder.\r\n" );
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document.write( "After reducing the volume, the equation has the form\r\n" );
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document.write( "    600 = Bh,      (2)\r\n" );
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document.write( "(the base area is the same; only the height of the cylinder changed from H to h).\r\n" );
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document.write( "Divide equation (2) by equation (1)  (both sides).  You will get  (the base area will be canceled on the way)\r\n" );
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document.write( "    \"600%2F750\" = \"h%2FH\",\r\n" );
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document.write( "or\r\n" );
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document.write( "    \"h%2FH\" = \"4%2F5\",   h = \"%284%2F5%29%2AH\" = \"%284%2F5%29%2A15\" = 4*3 = 12.\r\n" );
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document.write( "ANSWER.  After reducing the volume, the height of the cylinder decreased by 15-12 = 3 centimeters.\r\n" );
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