document.write( "Question 1195078: Throwing with the wind, a quarterback passes a football 90 ft in 2 s. Against the wind, the same pass would have traveled 70 ft in 2 s. Find the rate of the pass and the rate of the wind. \n" ); document.write( "
Algebra.Com's Answer #827423 by Theo(13342)\"\" \"About 
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rate * time = distance.
\n" ); document.write( "let p = the rate of the pass.
\n" ); document.write( "let w = the rate of the wind.
\n" ); document.write( "with the wind, the formula becomes:
\n" ); document.write( "(p + w) * 2 = 90
\n" ); document.write( "against the wind, the formula becomes:
\n" ); document.write( "(p - w) * 2 = 70
\n" ); document.write( "simplify both equations to get:
\n" ); document.write( "2p + 2w = 90
\n" ); document.write( "2p - 2w = 70
\n" ); document.write( "add the second equation to the first to get:
\n" ); document.write( "4p = 160
\n" ); document.write( "solve for p to get:
\n" ); document.write( "p = 40
\n" ); document.write( "the rate of the pass is 40 feet per second.
\n" ); document.write( "with the wind, you get:
\n" ); document.write( "(40 + w) * 2 = 90
\n" ); document.write( "simplify to get:
\n" ); document.write( "80 + 2w = 90
\n" ); document.write( "solve for w to get:
\n" ); document.write( "w = 5
\n" ); document.write( "against the wind, you get:\
\n" ); document.write( "(40 - w) * 2 = 70
\n" ); document.write( "solve for w to get:
\n" ); document.write( "w = 5
\n" ); document.write( "you get:
\n" ); document.write( "the rate of the pass is 40 feet per second.
\n" ); document.write( "the rate of the wind is 5 feet per second.
\n" ); document.write( "that's your solution.\r
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