document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=113675>Question 113675</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help.\r<BR>\n" );
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document.write( "Solve each of the following systems by addition. If a unique solution does not exist, state whether the system is inconsistent or dependent.\r<BR>\n" );
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document.write( "2x + 3y = 1<BR>\n" );
document.write( "5x + 3y = 16\r<BR>\n" );
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document.write( "Thanks<BR>\n" );
document.write( "JMS </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82742 by </B><A HREF=/tutors/aboutme.mpl?userid=Adam><B>Adam(64)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Adam><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82742\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Multiply the second equation by -1<BR>\n" );
document.write( "and get\r<BR>\n" );
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document.write( "2x + 3y = 1<BR>\n" );
document.write( "-5x - 3y = -16\r<BR>\n" );
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document.write( "add second equation to first\r<BR>\n" );
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document.write( "-3x + 0y = -15<BR>\n" );
document.write( "-3x = -15<BR>\n" );
document.write( "3x = 15<BR>\n" );
document.write( "x = 5\r<BR>\n" );
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document.write( "substitute this into any of the original equations<BR>\n" );
document.write( "2*5 + 3y = 1<BR>\n" );
document.write( "3y = -9<BR>\n" );
document.write( "y = -3\r<BR>\n" );
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document.write( "  </SPAN>\n" );
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