document.write( "Question 1195057: Graph a triangle ABC and perform a translation of (x + 4, y − 3) to create triangle A′B′C′.\r
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\n" ); document.write( "\n" ); document.write( "Describe the transformation using words. Make sure you refer to the characteristics and the coordinates.
\n" ); document.write( "Draw a line through points A and A′ and through points B and B′. What do you notice about the lines you drew? Do you think you would notice the same characteristics if you drew another line through points C and C′? How do you know?
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Algebra.Com's Answer #827399 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "She didn't answer your questions, but just drew the triangles, but\r\n" );
document.write( "didn't draw the line segments AA', BB', and CC'. But then, the lines \r\n" );
document.write( "would have been cluttered and hard to see.\r\n" );
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document.write( "Here is her second drawing, cropped,\r\n" );
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document.write( "Now I'll draw in the line segments AA', BB', CC' in red.\r\n" );
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document.write( "If you'll look carefully, you'll see they all look both parallel and\r\n" );
document.write( "equal in length.\r\n" );
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document.write( " \r\n" );
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document.write( "Let A = (p,q), B = (r,s), and C = (t,u). \r\n" );
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document.write( "She picked p=0, q=0, r=0, s=4, t=5, u=0, but you can pick ANY numbers you \r\n" );
document.write( "like for them as long as they're different points:\r\n" );
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document.write( "A = (p,q), so A' = (p+4, q-3)\r\n" );
document.write( "B = (r,s), so A' = (r+4, s-3)\r\n" );
document.write( "C = (t,u), so A' = (t+4, u-3)\r\n" );
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document.write( "\"matrix%281%2C3%2Cslope%2C+of%2C+%22AA%27%22%29\"\"%22%22=%22%22\"\"%28%28q-3%29-q%29%2F%28%28p%2B4%29-p%29\"\"%22%22=%22%22\"\"%28q-3-q%29%2F%28p%2B4-p%29\"\"%22%22=%22%22\"\"%28-3%29%2F%28%22%22+%2B+4%29\"\"%22%22=%22%22\"\"-3%2F4\"\r\n" );
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document.write( "\"matrix%281%2C3%2Cslope%2C+of%2C+%22BB%27%22%29\"\"%22%22=%22%22\"\"%28%28s-3%29-s%29%2F%28%28r%2B4%29-r%29\"\"%22%22=%22%22\"\"%28s-3-s%29%2F%28r%2B4-r%29\"\"%22%22=%22%22\"\"%28-3%29%2F%28%22%22+%2B+4%29\"\"%22%22=%22%22\"\"-3%2F4\"\r\n" );
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document.write( "\"matrix%281%2C3%2Cslope%2C+of%2C+%22CC%27%22%29\"\"%22%22=%22%22\"\"%28%28u-3%29-u%29%2F%28%28t%2B4%29-t%29\"\"%22%22=%22%22\"\"%28u-3-u%29%2F%28t%2B4-t%29\"\"%22%22=%22%22\"\"%28-3%29%2F%28%22%22+%2B+4%29\"\"%22%22=%22%22\"\"-3%2F4\"\r\n" );
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document.write( "They all have the same slope, -3/4, which means that the three lines will be\r\n" );
document.write( "parallel, regardless of what you choose for points (p,q), (r,s), and (t,u).\r\n" );
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document.write( "Not only that, but what about their lengths?\r\n" );
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document.write( "\"matrix%281%2C3%2Clength%2C+of%2C+%22AA%27%22%29\"\"%22%22=%22%22\"\"sqrt%28%28%28p%2B4%29%5E%22%22-p%29%5E2%2B%28%28q-3%29%5E%22%22-q%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%28%28p%2B4-p%29%5E2%2B%28q-3-q%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%28%28%22%22%2B4%29%5E2%2B%28-3%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%2816%2B9%29\"\"%22%22=%22%22\"\"sqrt%2825%29\"\"%22%22=%22%22\"\"5\"\r\n" );
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document.write( "\"matrix%281%2C3%2Clength%2C+of%2C+%22BB%27%22%29\"\"%22%22=%22%22\"\"sqrt%28%28%28r%2B4%29%5E%22%22-r%29%5E2%2B%28%28s-3%29%5E%22%22-s%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%28%28r%2B4-r%29%5E2%2B%28s-3-s%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%28%28%22%22%2B4%29%5E2%2B%28-3%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%2816%2B9%29\"\"%22%22=%22%22\"\"sqrt%2825%29\"\"%22%22=%22%22\"\"5\"\r\n" );
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document.write( "\"matrix%281%2C3%2Clength%2C+of%2C+%22CC%27%22%29\"\"%22%22=%22%22\"\"sqrt%28%28%28t%2B4%29%5E%22%22-t%29%5E2%2B%28%28u-3%29%5E%22%22-u%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%28%28t%2B4-t%29%5E2%2B%28u-3-u%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%28%28%22%22%2B4%29%5E2%2B%28-3%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%2816%2B9%29\"\"%22%22=%22%22\"\"sqrt%2825%29\"\"%22%22=%22%22\"\"5\"\r\n" );
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document.write( "The lengths of those parallel lines are also the same, 5.\r\n" );
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document.write( "The two triangles ABC and A'B'C' are also necessarily congruent, right? Or\r\n" );
document.write( "wrong?\r\n" );
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document.write( "Edwin
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