document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=113673>Question 113673</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ricardo is 4 years less than twice as old as his sister. The sum of their ages is 20. How old is Ricardo?<BR>\n" );
document.write( "2x-4=20 is what I have as the start of this equation, is this correct so far?<BR>\n" );
document.write( "I appreciate your time on this.\r<BR>\n" );
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document.write( "Thank You,<BR>\n" );
document.write( "Barb Neely </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82738 by </B><A HREF=/tutors/aboutme.mpl?userid=skigal545><B>skigal545(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=skigal545><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82738\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first you must come up with what x and y represent.<BR>\n" );
document.write( "x= his sister<BR>\n" );
document.write( "y= Richardo\r<BR>\n" );
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document.write( "Your first equation, 2x-4=20 is NOT correct because this is saying that 2 times the age minus four years is equal to both of their ages together. What it should say is 2x-4=y meaning two times his sisters age minus four years is equal to Richardo's age. The second equation would be their ages added together equals 20. so the equation would be x+y=20. From here you would get x or y alone in the second problem and plug it into the first.\r<BR>\n" );
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document.write( "x+y=20<BR>\n" );
document.write( "x-x+y=20-x<BR>\n" );
document.write( "y=20-x and plug this in.  </SPAN>\n" );
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