document.write( "Question 1195043: Two sides of a triangle field measure 325 meters and 278 meters. If these sides form an angle of 47°40’, what is the length of the fence that will surround the field? \n" ); document.write( "
Algebra.Com's Answer #827379 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Two sides of a triangle field measure 325 meters and 278 meters.
\n" ); document.write( "If these sides form an angle of 47°40’, what is the length of the fence that will surround the field?
\n" ); document.write( ":
\n" ); document.write( "Find the side opposite the angle
\n" ); document.write( "Change 47' 40\" to 47 + 40/60 = 47.67 degrees\r
\n" ); document.write( "\n" ); document.write( "use the law of cosines here: a^2 = b^2 + c^2 - 2bc Cos(A) where,
\n" ); document.write( "a = side opposite 47.67 degrees
\n" ); document.write( "b = 325 m
\n" ); document.write( "c= 278 m
\n" ); document.write( "A = 47.67 degrees
\n" ); document.write( ":
\n" ); document.write( "a^2 = 325^2 + 287^2 - 2(325*287) Cos(27.67)
\n" ); document.write( "a^2 = 105625 + 82369 - 186550 * .8856
\n" ); document.write( "a^2 = 187994 - 125662.7
\n" ); document.write( "a = \"sqrt%2862371.3%29\"
\n" ); document.write( "a = 249.7 meters is the 3rd side
\n" ); document.write( "then
\n" ); document.write( "325 + 287 + 249.7 = 861.7 meters to surround the field \n" ); document.write( "
\n" );