document.write( "Question 1195006: How would I go about sketching a graph for the total cost function, revenue function, and profit function:\r
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document.write( "C(x)=0.000002x^3-0.03x^2+400x+80,000\r
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document.write( "R(x)=-0.05x^2+600x\r
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document.write( "p(x)=-0.000002x^3-0.02x^2+200x-80,000 \n" );
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Algebra.Com's Answer #827341 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "I also recommend using technology like Desmos. \n" ); document.write( "GeoGebra is another useful tool you can use.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If your teacher wants you to \"plot by hand\", so to speak, then you'll need to plug in various x values to find corresponding y values. \n" ); document.write( "This way you'll get the (x,y) points that make up the curve.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For example, let's say we plugged in x = 10 into the C(x) function \n" ); document.write( "C(x)=0.000002x^3-0.03x^2+400x+80,000 \n" ); document.write( "C(10)=0.000002(10)^3-0.03(10)^2+400(10)+80,000 \n" ); document.write( "C(10)=83997.002\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You could compute that by pencil/paper, but I recommend using a calculator to do the third step.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From here we can say that the point (10, 83997.002) is on the C(x) cubic curve. \n" ); document.write( "Repeat this process for other x values to generate as many points as needed. \n" ); document.write( "Then draw a curve through them all the best you can.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "With regard to the revenue function R(x), we can factor out the GCF like so \n" ); document.write( "R(x)=-0.05x^2+600x \n" ); document.write( "R(x)=-0.05x(x-12000)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solving R(x) = 0 has us get: \n" ); document.write( "-0.05x(x-12000) = 0 \n" ); document.write( "-0.05x = 0 or x-12000 = 0 \n" ); document.write( "x = 0 or x = 12000 \n" ); document.write( "which are the two x intercepts. \n" ); document.write( "This is where the graph crosses the x axis.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's rewrite the revenue equation into vertex form \n" ); document.write( "Compare y = -0.05x^2+600x to y = ax^2+bx+c \n" ); document.write( "a = -0.05 \n" ); document.write( "b = 600 \n" ); document.write( "c = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The x coordinate of the vertex is \n" ); document.write( "h = -b/(2a) \n" ); document.write( "h = -600/(2(-0.05)) \n" ); document.write( "h = 6000 \n" ); document.write( "Or you could remark that the x coordinate of the vertex is the midpoint of the x intercepts \n" ); document.write( "h = (a+b)/2 = (0+12000)/2 = 6000 \n" ); document.write( "This midpoint property is directly due to symmetry.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then plug this into the original R(x) equation to find the y coordinate of the vertex \n" ); document.write( "y = -0.05x^2+600x \n" ); document.write( "y = -0.05(6000)^2+600(6000) \n" ); document.write( "y = 1,800,000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The vertex is located at (x,y) = (6000, 1800000)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The parabola opens downward because a < 0 \n" ); document.write( "Think of \"negative 'a' value makes a negative frown\" \n" ); document.write( "Because the parabola opens downward, we know that the R(x) function maxes out at the vertex. \n" ); document.write( "This helps determine the max revenue which is what many managers solely care about.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The x intercepts and vertex should give a rough idea of how the parabola looks (in a general sense). \n" ); document.write( "Plug in various other x values to get more points to plot on the parabola.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Unfortunately the cubic curves aren't as easy to determine their traits about them. \n" ); document.write( "Often with many cubics, it's very difficult to determine the x intercepts by hand. This is why a graphing calculator is preferred. \n" ); document.write( "You could use calculus methods, but this might be beyond the scope of the course. \n" ); document.write( " \n" ); document.write( " |