document.write( "Question 1194937: Solve the following practical application. Provide a systematic solution with
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\n" ); document.write( "\n" ); document.write( " A building 20 meters high stands on the top of a hill. Form a point at the foot of the hill,
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Algebra.Com's Answer #827255 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

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  • A = top of the building
  • B = base of the building
  • C = location of the observer
  • D = point needed to help form a right triangle
Further useful information:
  • The red segment (AB) is 20 meters in height
  • Angle BCD = 37°22′ = 37+22/60 = 37.36667° (approximate)
  • Angle ACD = 41°27′ = 41+27/60 = 41.45° (exact)
  • Segment BD is the height of the hill.
  • Angle BCD is marked in blue.
  • Angle ACD is marked in purple.
  • The dashed line (segment BC) is the hill itself.
Yet another hint: Break the figure into two separate right triangles ADC and BDC.
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