document.write( "Question 1194934: A pentagon is formed by adjoining a square to the base of an isosceles triangle. If the legs of the triangle have length 5 and the pentagon has perimeter 34, what is the area of the pentagon? \n" ); document.write( "
Algebra.Com's Answer #827224 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let x be the side length of the square. \n" ); document.write( "Then the perimeter of the pentagon is 3(x)+2(5)=34, which makes the side length of the square 8. \n" ); document.write( "If you cut the isosceles triangle in half, you get two congruent right triangles each with one leg 8/2=4 and hypotenuse 5, making the other leg of each of those triangles 2. \n" ); document.write( "So the area of the isosceles triangle (half base times height) is (1/2)(8)(3)=12. \n" ); document.write( "The area of the square is 8*8=64, so the area of the pentagon is 64+12=76. \n" ); document.write( "ANSWER: 76 \n" ); document.write( " \n" ); document.write( " |