document.write( "Question 1194908: The formular for the surface area is given by s={6r^2}+6rh a.make h the subject of the relation b.find h if r=2 ana 5=100 \n" ); document.write( "
Algebra.Com's Answer #827207 by ankor@dixie-net.com(22740)\"\" \"About 
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The formula for the surface area is given by s={6r^2}+6rh
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\n" ); document.write( " a. make h the subject of the relation
\n" ); document.write( "6r^2 + 6rh = s
\n" ); document.write( "Factor out 6r
\n" ); document.write( "6r(r+h) = s
\n" ); document.write( "r + h = \"s%2F%286r%29\"
\n" ); document.write( "h = \"s%2F%286r%29\" - r
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\n" ); document.write( " b. find h if r=2 and s=100
\n" ); document.write( "h = \"100%2F%286%2A2%29\" -2
\n" ); document.write( "h = \"100%2F12\" - 2
\n" ); document.write( "h = 8\"1%2F3\" - 2
\n" ); document.write( "h = 6\"1%2F3\"
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\n" ); document.write( "See if this checks out in the original formula; r=2 and h=6.3333
\n" ); document.write( "s = 6(2^2) + (6*2*6.3333)
\n" ); document.write( "s = 24 + 75.9996
\n" ); document.write( "s = 99.9996 ~ 100
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