document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1194902>Question 1194902</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year he earned $112 in interest. How much money was invested in each account?\r<BR>\n" );
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document.write( "Which of the following equations could be used to solve the problem?\r<BR>\n" );
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document.write( "0.02x + 0.04(800) = 112<BR>\n" );
document.write( "0.04x + 0.02(x + 800) = 112<BR>\n" );
document.write( "0.02x + 0.04(x + 800) = 112 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #827200 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=827200\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> it can be x for the smaller account at 0.02<BR>\n" );
document.write( "and x+800 for the larger account at 0.04<BR>\n" );
document.write( "The total is 0.02x0+0.04(x+800)=112<BR>\n" );
document.write( "C, </SPAN>\n" );
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