document.write( "Question 1194904: Please help me to solve this two students take a college entrance exam known to have a normal distribution of scores. The students receive raw scores of 63 and 93, which correspond to z scores (often called the standardized scores) of �1 and 1.5, respectively. Find the mean and standard deviation of the distribution of raw exam scores \n" ); document.write( "
Algebra.Com's Answer #827197 by Solver92311(821)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A raw score with a z-score of 1 IS the mean. A raw score with a z-score of 1.5 is one-half of a standard deviation above the mean. So the difference between the two raw scores is one-half of a standard deviation.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( "\n" ); document.write( "From \n" ); document.write( "I > Ø \n" ); document.write( " |