document.write( "Question 1194878: Please help me solve this question:log2{√(x³-2x²+x)}=1+log2(x-1) \n" ); document.write( "
Algebra.Com's Answer #827183 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"log%282%2Csqrt%28x%5E3-2x%5E2%2Bx%29%29=1%2Blog%282%2C%28x-1%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%282%2Csqrt%28x%5E3-2x%5E2%2Bx%29%29+-+log%282%2C%28x-1%29%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%282%2Csqrt%28x%5E3-2x%5E2%2Bx%29%2F%28x-1%29%29=1\"........since \"log%282%2C2%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%282%2Csqrt%28x%5E3-2x%5E2%2Bx%29%2F%28x-1%29%29=log%282%2C2%29\".........factor \"x%5E3-2x%5E2%2Bx=x+%28x+-+1%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%282%2Csqrt%28x+%28x+-+1%29%5E2%29%2F%28x-1%29%29=log%282%2C2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%282%2C+%28%28x+-+1%29sqrt%28x%29%29%2F%28x-1%29%29=log%282%2C2%29\"........simplify\r
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\n" ); document.write( "\n" ); document.write( "\"log%282%2C+sqrt%28x%29%29=log%282%2C2%29\"............since on both sides is log and base is same, we have\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28x%29=2\".........square both sides\r
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\n" ); document.write( "\n" ); document.write( "\"%28sqrt%28x%29%29%5E2=2%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"+x=4\"\r
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