document.write( "Question 1194836: Eight percent of all college graduates hired by companies stay with the same company for more than five years. The probability, rounded to four decimal places, that in a random sample of 11 such college graduates hired recently by companies, exactly 4 will stay with the same company for more than five years is \n" ); document.write( "
Algebra.Com's Answer #827125 by math_tutor2020(3817) ![]() You can put this solution on YOUR website! \n" ); document.write( "p = probability of success \n" ); document.write( "p = probability of a person staying with the same company for more than five years \n" ); document.write( "p = 0.08\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n = sample size \n" ); document.write( "n = 11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Binomial Probability Formula \n" ); document.write( "P(x) = ( nCx ) * p^x * (1-p)^(n-x) \n" ); document.write( "P(4) = ( 11C4 ) * 0.08^4 * (1-0.08)^(11-4) \n" ); document.write( "P(4) = ( 330 ) * 0.08^4 * (1-0.08)^(11-4) \n" ); document.write( "P(4) = 0.0075403009396 approximately \n" ); document.write( "P(4) = 0.0075\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The 11C4 refers to the nCr notation \n" ); document.write( "The scratch work is shown below \n" ); document.write( "n = 11, r = 4 \n" ); document.write( "n C r = (n!)/(r!(n-r)!) \n" ); document.write( "11 C 4 = (11!)/(4!*(11-4)!) \n" ); document.write( "11 C 4 = (11!)/(4!*7!) \n" ); document.write( "11 C 4 = (11*10*9*8*7!)/(4!*7!) \n" ); document.write( "11 C 4 = (11*10*9*8)/(4!) \n" ); document.write( "11 C 4 = (11*10*9*8)/(4*3*2*1) \n" ); document.write( "11 C 4 = (7920)/(24) \n" ); document.write( "11 C 4 = 330\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 0.0075 (approximate) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |