document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1194828>Question 1194828</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second angle of a triangle is four times the first angle. The third angle of the triangle is 18 degrees less than the first angle. Find each angle of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #827095 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=827095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The second angle of a triangle is four times the first angle. The third angle of the triangle is 18 degrees less than the first angle. Find each angle of the triangle.<BR>\n" );
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document.write( "S, F & T = second, first and third angles<BR>\n" );
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document.write( "S = 4F<BR>\n" );
document.write( "T = F - 18<BR>\n" );
document.write( "S + F + T = 180<BR>\n" );
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document.write( "4F + F + (F-18) = 180<BR>\n" );
document.write( "6F - 18 = 180<BR>\n" );
document.write( "F = 33 degrees<BR>\n" );
document.write( "etc </SPAN>\n" );
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