document.write( "Question 1194803: peter can finish a task 8 hours, and Sam can finish the same task twice as fast as Peter. If they work together, how many hours would it take to complete the task \n" ); document.write( "
Algebra.Com's Answer #827071 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let's say that the task is to move 80 boxes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Peter needs 8 hours to do the task on his own. \n" ); document.write( "His unit rate is 80/8 = 10 boxes per hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Sam works twice as fast as Peter, meaning his unit rate is 2*10 = 20 boxes per hour when Sam works alone.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If the two men work together, without hindering one another, then their combined unit rate is 10+20 = 30 boxes per hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = number of hours needed to complete the task if the two men work together\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(rate)*(time) = amount done \n" ); document.write( "(30 boxes per hour)*(x hours) = 80 boxes total \n" ); document.write( "30x = 80 \n" ); document.write( "x = 80/30 \n" ); document.write( "x = 8/3 \n" ); document.write( "x = (6+2)/3 \n" ); document.write( "x = 6/3+2/3 \n" ); document.write( "x = 2+2/3 \n" ); document.write( "x = 2 & 2/3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer as an improper fraction: 8/3 hours \n" ); document.write( "Answer as an mixed number: 2 & 2/3 hours \n" ); document.write( "Answer as a decimal: 2.67 hours approximately\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Side note: 2/3 hour = (2/3)*60 = 40 minutes \n" ); document.write( "Meaning that 8/3 hr = 2 & 2/3 hr = 2 hr + 40 min \n" ); document.write( " \n" ); document.write( " |