document.write( "Question 1194773: Mr. Jackson is looking at test scores for his Algebra 2 class. The scores on the Unit 2 Test follow a normal distribution, with a mean of 89 and a standard deviation of 3.\r
\n" ); document.write( "\n" ); document.write( "What percent of learners scored 86 or better? Show all work and provide the answer.
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Algebra.Com's Answer #827048 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "mu = 89 = population mean
\n" ); document.write( "sigma = 3 = population standard deviation\r
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\n" ); document.write( "\n" ); document.write( "For the raw score x = 86, it converts to the following z score
\n" ); document.write( "z = (x - mu)/sigma
\n" ); document.write( "z = (86 - 89)/3
\n" ); document.write( "z = (-3)/3
\n" ); document.write( "z = -1
\n" ); document.write( "This raw score is exactly one standard deviation below the mean.\r
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\n" ); document.write( "\n" ); document.write( "Now use a table like this one here
\n" ); document.write( "https://www.ztable.net/
\n" ); document.write( "Highlight the row that starts with -1 at the very left
\n" ); document.write( "Highlight the column that has 0 at the top
\n" ); document.write( "This row and column intersect at the value 0.15866
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\n" ); document.write( "\n" ); document.write( "This tells the reader
\n" ); document.write( "P(Z < -1) = 0.15866 approximately\r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "P(Z > -1) = 1 - P(Z > -1)
\n" ); document.write( "P(Z > -1) = 1 - 0.15866
\n" ); document.write( "P(Z > -1) = 0.84134
\n" ); document.write( "which is also approximate\r
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\n" ); document.write( "\n" ); document.write( "This means
\n" ); document.write( "P(x > 86) = 0.84134 approximately\r
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\n" ); document.write( "\n" ); document.write( "If you wanted, you can use a calculator to get better precision.\r
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\n" ); document.write( "\n" ); document.write( "Answer: About 84.134%
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