document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=113656>Question 113656</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Is it possible to build a triangle using the given side lengths? If so order the angle measures of the triangle from least to greatest. (Hint: Sketch each)<BR>\n" );
document.write( "RS= (sqaure root of) 46, ST= 3(square root of)5, RT=5. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82702 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> RS= (sqaure root of) 46 = 6.782...<BR>\n" );
document.write( "ST= 3(square root of)5 = 2.236...<BR>\n" );
document.write( "RT=5.<BR>\n" );
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document.write( "Since the sum of each pair of sides is greater than the remaining side<BR>\n" );
document.write( "a triangle can be formed.<BR>\n" );
document.write( "Angle opposite RS is T ; largest because opposite the largest side<BR>\n" );
document.write( "Angle opposite ST is R ; smallest because opposite the smallest side<BR>\n" );
document.write( "Angle opposite RT is S ; 2nd largest<BR>\n" );
document.write( "=============================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );