document.write( "Question 1194739: Please help me solve make g the subject of the relation. T=2 pie sqrt(l/g)}}} \n" ); document.write( "
Algebra.Com's Answer #826993 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"T=2pi%2Asqrt%28l%2Fg%29\"\r
\n" ); document.write( "\n" ); document.write( "\"T%2F%282pi%29=sqrt%28l%2Fg%29\"........square both sides\r
\n" ); document.write( "\n" ); document.write( "\"%28T%2F%282pi%29%29%5E2=%28sqrt%28l%2Fg%29%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"T%5E2%2F%284pi%5E2%29=l%2Fg\"......cross multiply\r
\n" ); document.write( "\n" ); document.write( "\"gT%5E2=%284pi%5E2%29%2Al\"\r
\n" ); document.write( "\n" ); document.write( "\"g=%284pi%5E2%2Al%29%2FT%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"g=%282pi%2FT%29%5E2%2Al\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );