document.write( "Question 1194738: Write the equation of the hyperbola with a center at (4, -1), transverse axis is parallel to the y-axis, distance between the foci is 10, one endpoint of the conjugate axis is at (6, -1).\r
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Algebra.Com's Answer #826992 by MathLover1(20850)\"\" \"About 
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given:\r
\n" ); document.write( "\n" ); document.write( " a center at (\"4\", \"-1\"),
\n" ); document.write( "transverse axis is parallel to the y-axis,
\n" ); document.write( "distance between the foci is \"10\",
\n" ); document.write( "one endpoint of the conjugate axis is at (\"6\",\"+-1\") \r
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\n" ); document.write( "\n" ); document.write( " if the transverse axis is parallel to the y-axis, use the standard form\r
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\n" ); document.write( "\"%28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1\"\r
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\n" ); document.write( "\n" ); document.write( "if a center at (\"4\", \"-1\")=> \"h=4\", \"k=-1\"\r
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\n" ); document.write( "\n" ); document.write( "the distance from the center to the given endpoint of the conjugate axis, and we know \"a=4+\" \r
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\n" ); document.write( "\n" ); document.write( "so far equation is\r
\n" ); document.write( "\n" ); document.write( " \"%28y-%28-1%29%29%5E2%2F4%5E2-%28x-4%29%5E2%2Fb%5E2=1\"\r
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\n" ); document.write( "\n" ); document.write( " \"%28y%2B1%29%5E2%2F16-%28x-4%29%5E2%2Fb%5E2=1\"\r
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\n" ); document.write( "\n" ); document.write( "The center is its midpoint, so the two foci are (\"4\",\"4\") and (\"4\",\"-6\").
\n" ); document.write( "\"c\" is distance between center and foci, so \"+c=5\"\r
\n" ); document.write( "\n" ); document.write( "The two blue lines are the latus rectums. They are given as \"9%2F2\", so by subtraction of half that or \"9%2F4\" from the x-coordinate of the focus (\"4\",\"4\"), we get that
\n" ); document.write( "the left end of the upper latus rectum is the point (\"7%2F4\",\"4%29.++The+hyperbola+goes+through+that+point.%0D%0A%0D%0A%7B%7B%7Bb%5E2=c%5E2-b%5E2=25-16=9\"\r
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\n" ); document.write( "\n" ); document.write( " \"%28y%2B1%29%5E2%2F16-%28x-4%29%5E2%2F9=1\"\r
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