document.write( "Question 113647: Solve the equation.\r
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document.write( "3x + x = 15-3
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Algebra.Com's Answer #82699 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! One of the first goals in solving first order equations (equations in which the unknown does \n" ); document.write( "not have an exponent of 2 or more) is to get all the terms containing the unknown on one side \n" ); document.write( "of the equal sign and all the numbers on the other side. This is already done in this equation. \n" ); document.write( ". \n" ); document.write( "Next you combine the terms on both sides. In this problem you combine 3x and +x by adding them \n" ); document.write( "to get 4x. On the other side of the equal sign you combine the 15 and the -3 to get 12. \n" ); document.write( "So you have reduced the equation to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Solve this by dividing both sides of this equation by the multiplier of the x term. In this \n" ); document.write( "case that multiplier is 4. So divide both sides of the equation by 4: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "On the left side the 4 in the denominator cancels with the 4 in the numerator and you are \n" ); document.write( "left with just x. On the right side the 4 in the denominator divides into the 12 in the \n" ); document.write( "numerator 3 times. So you are now left with: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "And this is the answer to the problem. \n" ); document.write( ". \n" ); document.write( "Keep these procedures in mind. They are typical steps to follow in solving any first order \n" ); document.write( "equation. \n" ); document.write( ". \n" ); document.write( " |