document.write( "Question 1194711: Measures of variability :
\n" ); document.write( "B : 75, 85, 92, 90, 73, 83\r
\n" ); document.write( "\n" ); document.write( "x̅ =
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\n" ); document.write( "\n" ); document.write( "Range:
\n" ); document.write( "R = H − L =\r
\n" ); document.write( "\n" ); document.write( "Mean Absolute Deviation:
\n" ); document.write( "MAD =\r
\n" ); document.write( "\n" ); document.write( "Standard Deviation:
\n" ); document.write( "SD =\r
\n" ); document.write( "\n" ); document.write( "Variance:
\n" ); document.write( "SD² = \n" ); document.write( "
Algebra.Com's Answer #826966 by Edwin McCravy(20065)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Measures of variability :\r\n" );
document.write( "B : 75, 85, 92, 90, 73, 83\r\n" );
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document.write( "x̅ = ADD THOSE NUMBERS UP AND THEN DIVIDE BY THE NUMBER OF NUMBERS\r\n" );
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document.write( "(x − x̅) = Substitute 75 for x and what you got for x̅\r\n" );
document.write( "|x − x̅| = Take the absolute value of the above\r\n" );
document.write( "(x − x̅)²= Square what you just got.\r\n" );
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document.write( "(x − x̅) = Substitute 85 for x and what you got for x̅\r\n" );
document.write( "|x − x̅| = Take the absolute value of the above\r\n" );
document.write( "(x − x̅)²= Square what you just got.\r\n" );
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document.write( "(x − x̅) = Substitute 92 for x and what you got for x̅\r\n" );
document.write( "|x − x̅| = Take the absolute value of the above\r\n" );
document.write( "(x − x̅)²= Square what you just got.\r\n" );
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document.write( "(x − x̅) = Substitute 90 for x and what you got for x̅\r\n" );
document.write( "|x − x̅| = Take the absolute value of the above\r\n" );
document.write( "(x − x̅)²= Square what you just got.\r\n" );
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document.write( "(x − x̅) = Substitute 73 for x and what you got for x̅\r\n" );
document.write( "|x − x̅| = Take the absolute value of the above\r\n" );
document.write( "(x − x̅)²= Square what you just got.\r\n" );
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document.write( "(x − x̅) = Substitute 83 for x and what you got for x̅\r\n" );
document.write( "|x − x̅| = Take the absolute value of the above\r\n" );
document.write( "(x − x̅)²= Square what you just got.\r\n" );
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document.write( "Range:\r\n" );
document.write( "R = H − L = The HIGHest number in B (at the top) MINUS the LEAST number in B.\r\n" );
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document.write( "Mean Absolute Deviation:\r\n" );
document.write( "MAD = Add all the absolute values you found above and then divide by the number\r\n" );
document.write( "of numbers.\r\n" );
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document.write( "Standard Deviation: (This was asked in the wrong place, for it's the square root\r\n" );
document.write( "of what is asked below. So I'll answer it below the next instruction.  \r\n" );
document.write( "SD =\r\n" );
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document.write( "Variance:\r\n" );
document.write( "SD² = ADD all the (x − x̅)2 and then divide by either:\r\n" );
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document.write( "(a) the number of numbers if B is a population.\r\n" );
document.write( "(b) one less than the number of numbers if B is a sample from a population.\r\n" );
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document.write( "Standard Deviation: \r\n" );
document.write( "SD = Take the square root of what you got for the Variance.\r\n" );
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document.write( "Edwin
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