document.write( "Question 1194702: You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard deviation is approximately σ=27.3. You would like to be 95% confident that your estimate is within 2 of the true population mean. How large of a sample size is required? \r
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document.write( "I keep getting 264 as the answer which it says is incorrect, maybe it is my z-score? \n" );
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Algebra.Com's Answer #826954 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "At 95% confidence, the z critical value is roughly z = 1.960 \n" ); document.write( "Use a Z table or calculator to determine this. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We're told that sigma = 27.3 \n" ); document.write( "The error we want is E = 2 or smaller.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's compute the min sample size. \n" ); document.write( "n = (z*sigma/E)^2 \n" ); document.write( "n = (1.960*27.3/2)^2 \n" ); document.write( "n = 715.776516 \n" ); document.write( "n = 716 \n" ); document.write( "Always round up to the nearest whole number. \n" ); document.write( "If we got something like 715.00001, then we would still round up to 716 to clear the hurdle.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here is a short derivation of where this version of min sample size formula comes from \n" ); document.write( "E = margin of error \n" ); document.write( "E = z*sigma/sqrt(n) \n" ); document.write( "E*sqrt(n) = z*sigma \n" ); document.write( "sqrt(n) = z*sigma/E \n" ); document.write( "n = (z*sigma/E)^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 716 \n" ); document.write( " \n" ); document.write( " |