document.write( "Question 1194662: The width of a rectangle is 15 less than twice its length. If the perimeter of the rectangle is 30 feet, what are the dimensions? \n" ); document.write( "
Algebra.Com's Answer #826907 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
These will all work the same no matter what the given values, if the values are meaningful.\r
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\n" ); document.write( "The width of a rectangle is k less than r times its length, L. If the perimeter of the rectangle is p feet, what are the dimensions?
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\n" ); document.write( "\n" ); document.write( "Dimensions,
\n" ); document.write( "L, length
\n" ); document.write( "rL-k, width
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\n" ); document.write( "p, perimeter
\n" ); document.write( "UNKNOWN VARIABLE, L\r
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\n" ); document.write( "\n" ); document.write( "\"highlight_green%28%28rL-k%29%2BL=p%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"rL-k%2BL=p%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28r%2B1%29L-k=p%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28r%2B1%29L=p%2F2%2Bk\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight_green%28L=%28p%2F2%2Bk%29%2F%28r%2B1%29%29\"
\n" ); document.write( "and you can plug in the given values and compute L.\r
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\n" ); document.write( "\n" ); document.write( "\"L=%2830%2F2%2B15%29%2F%282%2B1%29\"
\n" ); document.write( "\"L=%2815%2B15%29%2F3\"
\n" ); document.write( "\"L=10\"
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