document.write( "Question 1194629: Divide the circle area (with radius r) with one cut (one tendon) in a ratio of 1:2. \n" ); document.write( "
Algebra.Com's Answer #826890 by Edwin McCravy(20064)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "I'm not sure what you want here.  But I'll do enough of it to get you\r\n" );
document.write( "so you can finish.\r\n" );
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document.write( "Let AB be the chord which divides the area of the circle so that\r\n" );
document.write( "the area above AB is 1/3 of the area of the circle \"A=pi%2Ar%5E2\".\r\n" );
document.write( "Then the area below AB will be 2/3 of the area of the circle. Then\r\n" );
document.write( "they will be in the ratio 1:2\r\n" );
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document.write( "We draw in two radii to A and B.\r\n" );
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document.write( "First we find the area of the sector AOB (\"piece of pie\") \r\n" );
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document.write( "\"Area\"\"%22%22=%22%22\"\"%28theta%2F360%29%2Api%2Ar%5E2\"\r\n" );
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document.write( "In this case, \"theta=%22%3CAOB%22\"\r\n" );
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document.write( "\"Area\"\"%22%22=%22%22\"\"%28%22%3CAOB%22%2F360%29%2Api%2Ar%5E2\"\r\n" );
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document.write( "We must subtract the area of triangle AOB to get the area\r\n" );
document.write( "above AB.\r\n" );
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document.write( "If a triangle has two sides with lengths x and y, and the \r\n" );
document.write( "angle between these two sides is θ degrees, then the area \r\n" );
document.write( "of the triangle is given by the equation \r\n" );
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document.write( "\"Area\"\"%22%22=%22%22\"\"+expr%281%2F2%29x%2Ay%2Asin%28theta%29\"\r\n" );
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document.write( "In this case, x and y both equal the radius r, and \"theta=%22%3CAOB%22\"\r\n" );
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document.write( "\"Area\"\"%22%22=%22%22\"\"+expr%281%2F2%29r%2Ar%2Asin%28%22%3CAOB%22%29\"\r\n" );
document.write( "\"Area\"\"%22%22=%22%22\"\"+expr%281%2F2%29r%5E2%2Asin%28%22%3CAOB%22%29\"\r\n" );
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document.write( "The area above AB is\r\n" );
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document.write( "\"%28%22%3CAOB%22%2F360%29%2Api%2Ar%5E2\"\"%22%22-%22%22\"\"+expr%281%2F2%29r%5E2%2Asin%28%22%3CAOB%22%29\"\r\n" );
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document.write( "This must equal 1/3 of the area, which is \"expr%281%2F3%29%2Api%2Ar%5E2\" \r\n" );
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document.write( "So the equation is \r\n" );
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document.write( "\"%28%22%3CAOB%22%2F360%29%2Api%2Ar%5E2\"\"%22%22-%22%22\"\"+expr%281%2F2%29r%5E2%2Asin%28%22%3CAOB%22%29\"\"%22%22=%22%22\"\"expr%281%2F3%29%2Api%2Ar%5E2\" \r\n" );
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document.write( "We divide through by r2\r\n" );
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document.write( "\"%28%22%3CAOB%22%2F360%29%2Api\"\"%22%22-%22%22\"\"+expr%281%2F2%29%2Asin%28%22%3CAOB%22%29\"\"%22%22=%22%22\"\"expr%281%2F3%29%2Api\"\r\n" );
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document.write( "You can only solve that for \"%22%3CAOB%22\" with technology.\r\n" );
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document.write( "I used a TI-84 Plus.  I got 149.27417o\r\n" );
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document.write( "Use that to find whatever else your teacher wants. \r\n" );
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document.write( "Edwin
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