document.write( "Question 113360: The length of a rectangle is 4 less than 3 times the width. If the perimeter is 40, find the dimensions of the rectangle.
\n" ); document.write( "I really need help!! \n" ); document.write( "
Algebra.Com's Answer #82686 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
:
\n" ); document.write( "Let x = the width
\n" ); document.write( ":
\n" ); document.write( "It says,\"The length of a rectangle is 4 less than 3 times the width.\" write that as:
\n" ); document.write( "L = 3x - 4
\n" ); document.write( ":
\n" ); document.write( " If the perimeter is 40, find the dimensions of the rectangle.
\n" ); document.write( ":
\n" ); document.write( "We know: 2L + 2W = 40
\n" ); document.write( ":
\n" ); document.write( "Substitute (3x-4) for L and x for W
\n" ); document.write( "2(3x-4) + 2x = 40
\n" ); document.write( ":
\n" ); document.write( "6x - 8 + 2x = 40; Multiplied what's inside the brackets
\n" ); document.write( ":
\n" ); document.write( "6x + 2x = 40 + 8; do some basic algebra to find x; (added 8 to both sides)
\n" ); document.write( ":
\n" ); document.write( "8x = 48
\n" ); document.write( ":
\n" ); document.write( "x = 48/8
\n" ); document.write( ":
\n" ); document.write( "x = 6 which is the width
\n" ); document.write( ":
\n" ); document.write( "It said that L = 3x - 4, therefore:
\n" ); document.write( "L = 3(6) - 4
\n" ); document.write( "L = 18 - 4
\n" ); document.write( "L = 14; is the length
\n" ); document.write( ":
\n" ); document.write( "Check our solutions in the perimeter:
\n" ); document.write( "2(14) + 2(6) =
\n" ); document.write( "28 + 12 = 40
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Is this the help you need? Do you have any questions? \n" ); document.write( "
\n" );