document.write( "Question 1194586: Three interior angles of a pentagon are each 3y and the remaining each twice the first three. Find the value of y. Please help me solve this \n" ); document.write( "

Algebra.Com's Answer #826817 by ikleyn(52794) $\"\"$ $\"About$

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\n" ); document.write( "Three interior angles of a pentagon are each 3y and the remaining each twice the first three.
\n" ); document.write( "Find the value of y. Please help me solve this
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document.write( "The sum of interior angles of any n-gon is  (n-2)*180°.\r\n" );
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document.write( "For a pentagon, it is  (5-2)*180° = 3*180° = 540°.\r\n" );
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document.write( "The three angles are 3y each;  the remaining two angles are 2*(3y) = 6y each.\r\n" );
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document.write( "An equation to find y is\r\n" );
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document.write( "    3y + 3y + 3y + 6y + 6y = 540°,\r\n" );
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document.write( "or\r\n" );
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document.write( "    21y = 540  degrees,\r\n" );
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document.write( "which implies\r\n" );
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document.write( "    y = 540/21 = 180/7.\r\n" );
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document.write( "ANSWER.  The value of y is  180/7 degrees.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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\n" ); document.write( "\n" ); document.write( "Had the author be willing to create an educationally valuable problem,
\n" ); document.write( "he (or she) would take care to pick up more rounded numbers.\r
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