document.write( "Question 1194573: In how many ways can 4 people be seated in a row of 12 chairs \n" ); document.write( "

Algebra.Com's Answer #826811 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "First person can seat at any of 12 seats, giving 12 options.\r\n" );
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document.write( "Second person can seat at any of remaining 11 seats, giving 11 options.\r\n" );
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document.write( "Third person can seat at any of remaining 10 seats, giving 10 options.\r\n" );
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document.write( "Fourth person can seat at any of remaining 9 seats, giving 9 options.\r\n" );
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document.write( "The total number of possible seating arrangements is  12*11*10*9 = 11880.    ANSWER\r\n" );
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document.write( "It is the product of 4 consecutive integers numbers in descending order, starting from the number of 12.\r\n" );
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\n" ); document.write( "\n" ); document.write( "To see many similar (and different) solved problems, look into the lesson\r
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\n" ); document.write( "\n" ); document.write( " - Special type permutations problems \r
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