document.write( "Question 17089: Suppose you throw a rock upward from a height of 64 feet with an intial velocity of 48 feet per second the rock will hit the ground after __ seconds.
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Algebra.Com's Answer #8268 by Earlsdon(6294)\"\" \"About 
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The height, h, of an object thrown upward from an initial height, Ho, with an initial velocity, Vo, is given by the function h as a function of time, t:\r
\n" ); document.write( "\n" ); document.write( "\"h%28t%29+=+-16t%5E2+%2B+Vot+%2B+Ho\"\r
\n" ); document.write( "\n" ); document.write( "Since Vo = 48 ft/sec and Ho 64 ft, then:\r
\n" ); document.write( "\n" ); document.write( "\"h%28t%29+=+-16t%5E2+%2B+48t+%2B+64\" You want to know at what time, t, will the rock hit the ground (h = 0). Set the above function = 0.\r
\n" ); document.write( "\n" ); document.write( "\"-16t%5E2+%2B+48t+%2B+64+=+0\" Solve this quadratic equation for t. First, factor -16.
\n" ); document.write( "\"-16%28t%5E2+-+3t+-+4%29+=+0\" Apply the zero products principle.
\n" ); document.write( "\"t%5E2+-+3t+-+4+=+0\" Factor.
\n" ); document.write( "\"%28t+-+4%29%28t+%2B+1%29\" Again, apply the zero products principle.
\n" ); document.write( "\"t+-+4+=+0\" and/or \"t+%2B+1+=+0\"\r
\n" ); document.write( "\n" ); document.write( "If t - 4 = 0, then t = 4 seconds
\n" ); document.write( "If t + 1 = 0, then t = -1 second...Discard this solution as negative time is not meaningful in this problem.\r
\n" ); document.write( "\n" ); document.write( "The rock hits the ground after 4 seconds.
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