document.write( "Question 1194563: Suppose the functions f, g, h, r and l are defined as follows:
\n" ); document.write( "f(x)=1/3log3(1/4)+log3x\r
\n" ); document.write( "\n" ); document.write( "write down the domain of f and then solve the equation f(x)=-log1/2 3sqaure root x
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Algebra.Com's Answer #826797 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "I can guess that the given function is

\n" ); document.write( "\"%281%2F3%29log%283%2C%281%2F4%29%29%2Blog%283%2C%28x%29%29\"

\n" ); document.write( "Using rules for logarithms, we can write that as a single logarithm:

\n" ); document.write( "\"log%283%2C%28%281%2F4%29%5E%281%2F3%29%29%29%2Blog%283%2C%28x%29%29\"
\n" ); document.write( "\"log%283%2C%28%28%281%2F4%29%5E%281%2F3%29%29%28x%29%29%29\"

\n" ); document.write( "\"%281%2F4%29%5E%281%2F3%29\" is a positive real number, so\"log%283%2C%28%281%2F4%29%5E%281%2F3%29%29%29\" is a real number. So there are no restrictions on the value of x.

\n" ); document.write( "ANSWER 1: The domain of f(x) is all real numbers

\n" ); document.write( "I can't respond to the second question, because I don't know how to interpret

\n" ); document.write( "\"-log1/2 3sqaure root x\"

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