document.write( "Question 1194447: IN HOW MANY WAYS CAN 6 INDIVIDUALS BE SEATED IN A ROUND TABLE WITH
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document.write( "6 CHAIRS?
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document.write( "A.) SUPPOSE 2 PERSONS WANTED TO BE SEATED SIDE BY SIDE ,IN HOW MANY
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document.write( " WAYS CAN THEY DO IT?
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document.write( "B.) IN HOW MANY WAYS CAN THESE 6 INDIVIDUALS ARRANGE THEMSELVES IF
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document.write( "2 AMONG THEM REFUSE TO SIT TOGETHER? \n" );
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Algebra.Com's Answer #826781 by Edwin McCravy(20065) You can put this solution on YOUR website! IN HOW MANY WAYS CAN 6 INDIVIDUALS BE SEATED IN A ROUND TABLE \n" ); document.write( "WITH 6 CHAIRS?\r \n" ); document.write( "\n" ); document.write( "The table and chairs are all resting on a huge lazy Susan. \n" ); document.write( "If it weren't on a huge lazy Susan, the answer would be 6!, \n" ); document.write( "but since we can turn the huge lazy Susan so that any one of \n" ); document.write( "the 6 can face north, we must divide by 6, making it 5! = 120 \n" ); document.write( "ways.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A.) SUPPOSE 2 PERSONS WANTED TO BE SEATED SIDE BY SIDE ,IN HOW \n" ); document.write( "MANY WAYS CAN THEY DO IT?\r \n" ); document.write( "\n" ); document.write( "They can be seated together in 2 ways. Then there are 4 single \n" ); document.write( "people and one pair of people. That would be 5! if the table \n" ); document.write( "weren't on a lazy susan. So we must divide by 5. So the answer \n" ); document.write( "is (2)(4!) = 24.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "B.) IN HOW MANY WAYS CAN THESE 6 INDIVIDUALS ARRANGE THEMSELVES \n" ); document.write( "IF 2 AMONG THEM REFUSE TO SIT TOGETHER?\r \n" ); document.write( "\n" ); document.write( "We subtract the 24 from the 120. 120-24 = 96 ways.\r \n" ); document.write( "\n" ); document.write( "Edwin \n" ); document.write( " |