document.write( "Question 1194447: IN HOW MANY WAYS CAN 6 INDIVIDUALS BE SEATED IN A ROUND TABLE WITH
\n" ); document.write( "6 CHAIRS?
\n" ); document.write( "A.) SUPPOSE 2 PERSONS WANTED TO BE SEATED SIDE BY SIDE ,IN HOW MANY
\n" ); document.write( " WAYS CAN THEY DO IT?
\n" ); document.write( "B.) IN HOW MANY WAYS CAN THESE 6 INDIVIDUALS ARRANGE THEMSELVES IF
\n" ); document.write( "2 AMONG THEM REFUSE TO SIT TOGETHER?
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Algebra.Com's Answer #826781 by Edwin McCravy(20065)\"\" \"About 
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IN HOW MANY WAYS CAN 6 INDIVIDUALS BE SEATED IN A ROUND TABLE
\n" ); document.write( "WITH 6 CHAIRS?\r
\n" ); document.write( "\n" ); document.write( "The table and chairs are all resting on a huge lazy Susan.
\n" ); document.write( "If it weren't on a huge lazy Susan, the answer would be 6!,
\n" ); document.write( "but since we can turn the huge lazy Susan so that any one of
\n" ); document.write( "the 6 can face north, we must divide by 6, making it 5! = 120
\n" ); document.write( "ways.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "A.) SUPPOSE 2 PERSONS WANTED TO BE SEATED SIDE BY SIDE ,IN HOW
\n" ); document.write( "MANY WAYS CAN THEY DO IT?\r
\n" ); document.write( "\n" ); document.write( "They can be seated together in 2 ways. Then there are 4 single
\n" ); document.write( "people and one pair of people. That would be 5! if the table
\n" ); document.write( "weren't on a lazy susan. So we must divide by 5. So the answer
\n" ); document.write( "is (2)(4!) = 24.\r
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\n" ); document.write( "\n" ); document.write( "B.) IN HOW MANY WAYS CAN THESE 6 INDIVIDUALS ARRANGE THEMSELVES
\n" ); document.write( "IF 2 AMONG THEM REFUSE TO SIT TOGETHER?\r
\n" ); document.write( "\n" ); document.write( "We subtract the 24 from the 120. 120-24 = 96 ways.\r
\n" ); document.write( "\n" ); document.write( "Edwin
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