document.write( "Question 1194539: Hi
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document.write( "In a 3 digit number the units digit is 3 more than the tens digit and the sum of the digits is 11. If the units and hundreds digits are interchanged the number increased by 99.
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document.write( "What is original number.
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document.write( "Thanks \n" );
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Algebra.Com's Answer #826769 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "When the digits of a 3-digit number are reversed, the difference between the new number and the original number is 99 times the difference between the units digit and hundreds digit. \n" ); document.write( "In this problem, the number is increased by 99 when the digits are reversed; that means in the original number the hundreds digit is 1 less than the units digit. \n" ); document.write( "Then, given that the units digit is 3 more than the tens digit, we have \n" ); document.write( "x = tens digit \n" ); document.write( "x+3 = units digit (3 more than the tens digit) \n" ); document.write( "x+2 = hundreds digit (1 less than the units digit) \n" ); document.write( "The sum of the digits is 11: \n" ); document.write( "x+x+3+x+2 = 11 \n" ); document.write( "3x+5=11 \n" ); document.write( "3x=6 \n" ); document.write( "x=2 \n" ); document.write( "The tens digit is x=2; the units digit is x+3=5; the hundreds digit is x+2=4. \n" ); document.write( "ANSWER: 425 \n" ); document.write( " \n" ); document.write( " |